Giancoli 5th Ed.

Hwk 14  (Due 12/9/22)        10 point hwk
Ch. 32 P. 1,2,5,6,10,16
    MiscQ. 1-8 all 

Problems: 
1. (a) do = 630 mm
   (b) do = 635 mm
2. (a) converging lens
   (b) P = 1/f = 6.06 Diopters
5. (a) di = 106 mm
   (b) di = 109 mm
   (c) di = 117 mmm
   (d) Use 1/do,min + 1/di,max = 1/f with di,max=132mm
       do,min = 513 mm (.513 m)
6. (a) di = -32 cm
         Image is on front side of lens (same as stamp).
   (b) m=-di/do = +2.15 x
10. (a) real image implies f > 0, di>0, and M<0.
        So di=-mdo = 2.5do. 
        do = 105 mm
    (b) do = 45 mm
16. (a) do = 0.105 m
    hi = m*ho = (-di/do)*ho = 5118 mm, or 5.1 m.
    (b) The image is unchanged, but the image
        distance for the 2nd lens has changed
        di2 = (do2f2)/(do2-f2) = 29.1 cm to
        the right of diverging lens.

MiscQ.
1. c
2. e
3. c
4. d
5. c
6. c
7. d
8. e


Please check   Tot= 10 pts
Prob.    (1pt each)
MiscQ.   (0.5 pt each)