Giancoli 5th Ed. Hwk 14 (Due 12/9/22) 10 point hwk Ch. 32 P. 1,2,5,6,10,16 MiscQ. 1-8 all Problems: 1. (a) do = 630 mm (b) do = 635 mm 2. (a) converging lens (b) P = 1/f = 6.06 Diopters 5. (a) di = 106 mm (b) di = 109 mm (c) di = 117 mmm (d) Use 1/do,min + 1/di,max = 1/f with di,max=132mm do,min = 513 mm (.513 m) 6. (a) di = -32 cm Image is on front side of lens (same as stamp). (b) m=-di/do = +2.15 x 10. (a) real image implies f > 0, di>0, and M<0. So di=-mdo = 2.5do. do = 105 mm (b) do = 45 mm 16. (a) do = 0.105 m hi = m*ho = (-di/do)*ho = 5118 mm, or 5.1 m. (b) The image is unchanged, but the image distance for the 2nd lens has changed di2 = (do2f2)/(do2-f2) = 29.1 cm to the right of diverging lens. MiscQ. 1. c 2. e 3. c 4. d 5. c 6. c 7. d 8. e Please check Tot= 10 pts Prob. (1pt each) MiscQ. (0.5 pt each)