Giancoli 5th Ed. Ch. 21 P. 22-25, 27, 30, 33, 39, 47, 48, 55, 57 Q. 15-26 (don't write out) MiscQ. 4,5,7,8,11 Problems 22. E = F/q so F=qE=3.62e-16 N west (or -i-hat) 23. E = F/q = 1.05e+5 N/C south 24. E=kQ/r^2 = 3.95e+6 N/C upward 25. E = F/q = 195 N/C j-hat 27. F_net = ma = qE so a=qE/m = 1.33e+14 m/s^2 30. Use result of Ex 21-12. E=-4.7e+11 i -1.6e+11 j N/C 33. Use cancellation due to symmetry. E_tot = k (q_33-q_22) / r^2 = 9x10^2 (33.8-22)x10^(-6) / (.301)^2 = 1.17E+6 N/C towards the -33.8 uC charge 39. E = kQ(x+l/2) kQ(x-l/2) ---------- + ------------- i (to right) [(x+l/2)^2 + R^2]^3/2 [(x-l/2)^2 + R^2]^3/2 47. Etot = 4k(lambda) l z ---------------- (z^2+(l/2)^2)(z^2+2(l/2)^2)^1/2 or Etot = 8(lambda)l z ---------------- (pi)(e0)(4z^2+l^2)(4z^2+2l^2)^1/2 48. E = 2k(lambda)/R sin(theta) (-i) (left) 55. a) E points to the right (in order to create force to left on e-) b) E = 32 N/C 57. x ~ -10 m y ~ 9.5 m Misconceptual Questions 4. d 5. b 7. a 8. c 11. d